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6x^2-5000=0
a = 6; b = 0; c = -5000;
Δ = b2-4ac
Δ = 02-4·6·(-5000)
Δ = 120000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120000}=\sqrt{40000*3}=\sqrt{40000}*\sqrt{3}=200\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{3}}{2*6}=\frac{0-200\sqrt{3}}{12} =-\frac{200\sqrt{3}}{12} =-\frac{50\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{3}}{2*6}=\frac{0+200\sqrt{3}}{12} =\frac{200\sqrt{3}}{12} =\frac{50\sqrt{3}}{3} $
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